2{{h}^{2}}=162\,\,C{{m}^{2}}\] \[\RIGHTARROW \]\[{{h}^{2}}=81\Rightarrow h=9\Rightarrow b=2h=18\,\,cm\]

"> 2{{h}^{2}}=162\,\,C{{m}^{2}}\] \[\RIGHTARROW \]\[{{h}^{2}}=81\Rightarrow h=9\Rightarrow b=2h=18\,\,cm\]

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The base of a parallelogram is twice its height. If the area of parallelogram is\[162\,\,c{{m}^{2}},\] then find the base.

10th Class Mathematics in 10th Class 11 months ago

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\[b=2h:A=b\times h=2{{h}^{2}}=162\,\,C{{m}^{2}}\] \[\RIGHTARROW \]\[{{h}^{2}}=81\Rightarrow h=9\Rightarrow b=2h=18\,\,cm\]

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