PERIMETER = 132 \[\therefore \] \[2\left( b+\frac{6}{5}b \RIGHT)=132\Rightarrow \,b=30\,m\] HENCE, length \[=\frac{6}{5}\times 30\,=36\,m\] And area = length \[\times \] breadth \[=36\times 30=1080\,{{m}^{2}}\].

"> PERIMETER = 132 \[\therefore \] \[2\left( b+\frac{6}{5}b \RIGHT)=132\Rightarrow \,b=30\,m\] HENCE, length \[=\frac{6}{5}\times 30\,=36\,m\] And area = length \[\times \] breadth \[=36\times 30=1080\,{{m}^{2}}\].

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The length of a rectangle is \[\frac{6}{5}\] th of its breadth. If its perimeter is 132m, its area will be............

10th Class Mathematics in 10th Class 11 months ago

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Let breadth = b m Then, length \[=\frac{6}{5}bm\] \[\because \] PERIMETER = 132 \[\therefore \] \[2\left( b+\frac{6}{5}b \RIGHT)=132\Rightarrow \,b=30\,m\] HENCE, length \[=\frac{6}{5}\times 30\,=36\,m\] And area = length \[\times \] breadth \[=36\times 30=1080\,{{m}^{2}}\].

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