63\]\[\Rightarrow \]\[36\,\text{etc}\text{.}\] \[\therefore \]    \[\frac{12}{3}+\frac{27}{3}=49\Rightarrow 94.\] \[\therefore \]    \[2\,\,1\,\,5={{2}^{2}}\,1\,\,{{5}^{2}}=4\,\,1\,\,2\,5\]

"> 63\]\[\Rightarrow \]\[36\,\text{etc}\text{.}\] \[\therefore \]    \[\frac{12}{3}+\frac{27}{3}=49\Rightarrow 94.\] \[\therefore \]    \[2\,\,1\,\,5={{2}^{2}}\,1\,\,{{5}^{2}}=4\,\,1\,\,2\,5\]

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DIRECTIONS: In each of the following questions, three statements of numbers following same rules are given. Find the rule and accordingly find the value of the number? If 3 + 9 = 31; 15 + 12 = 45; 18 + 9 = 36, then 12 + 27 =?

7th Class Mathematics in 7th Class . 10 months ago

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The rule is: Divide each number by 3 and write the quotients in the reverse order. \[\frac{3}{3}+\frac{9}{3}=13\]       \[\Rightarrow \] \[31;\frac{15}{3}+\frac{12}{3}=45;\] \[18+9=\frac{18}{3}+\frac{9}{3}=63\]\[\Rightarrow \]\[36\,\text{etc}\text{.}\] \[\therefore \]    \[\frac{12}{3}+\frac{27}{3}=49\Rightarrow 94.\] \[\therefore \]    \[2\,\,1\,\,5={{2}^{2}}\,1\,\,{{5}^{2}}=4\,\,1\,\,2\,5\]

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Posted on 25 Aug 2024, this text provides information on 7th Class related to Mathematics in 7th Class. Please note that while accuracy is prioritized, the data presented might not be entirely correct or up-to-date. This information is offered for general knowledge and informational purposes only, and should not be considered as a substitute for professional advice.

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