USING the correct symbols, we have Given expression \[=\frac{(36-4)\DIV 8-4}{4\times 8-2\times 16+1}=\frac{32\div 8-4}{32-32+1}=\frac{4-4}{0+1}\] \[=0.\] "> USING the correct symbols, we have Given expression \[=\frac{(36-4)\DIV 8-4}{4\times 8-2\times 16+1}=\frac{32\div 8-4}{32-32+1}=\frac{4-4}{0+1}\] \[=0.\] ">
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If \[\div \] means\[~+,\,\,-\] means \[\div ,\,\,\times \] means \[-\] and \[+\] means \[\times ,\] then\[\frac{(36\times 4)-8\times 4}{4+8+2+16\div 1}=\]?

7th Class Mathematics in 7th Class . 10 months ago

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USING the correct symbols, we have Given expression \[=\frac{(36-4)\DIV 8-4}{4\times 8-2\times 16+1}=\frac{32\div 8-4}{32-32+1}=\frac{4-4}{0+1}\] \[=0.\]
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