LENGTH and width be \[L\] & B respectively. Then the initial area\[=l\times b\] According to the question, New length and width will be \[2L\] and \[2b\] respectively. \[\therefore \] New area\[=2l\times 2b=4lb\] Increment in area \[=\frac{4lb-lb}{lb}\times 100%=300%.\]

"> LENGTH and width be \[L\] & B respectively. Then the initial area\[=l\times b\] According to the question, New length and width will be \[2L\] and \[2b\] respectively. \[\therefore \] New area\[=2l\times 2b=4lb\] Increment in area \[=\frac{4lb-lb}{lb}\times 100%=300%.\]

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If each of the dimensions of a rectangle is increased by 100% its area is increased by

7th Class Mathematics in 7th Class 11 months ago

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Let the initial LENGTH and width be \[L\] & B respectively. Then the initial area\[=l\times b\] According to the question, New length and width will be \[2L\] and \[2b\] respectively. \[\therefore \] New area\[=2l\times 2b=4lb\] Increment in area \[=\frac{4lb-lb}{lb}\times 100%=300%.\]

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