SQUARE be \[9{{x}^{2}}\] and \[{{x}^{2}}\] respectively. Then the sides of them will be \[\SQRT{9{{x}^{2}}}\]and\[\sqrt{{{x}^{2}}}\]i.e,\[3x\]and\[x\]respectively. Hence, the RATIO of their perimeter \[=\frac{4\times 3x}{4\times x}=3:1\]

"> SQUARE be \[9{{x}^{2}}\] and \[{{x}^{2}}\] respectively. Then the sides of them will be \[\SQRT{9{{x}^{2}}}\]and\[\sqrt{{{x}^{2}}}\]i.e,\[3x\]and\[x\]respectively. Hence, the RATIO of their perimeter \[=\frac{4\times 3x}{4\times x}=3:1\]

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If the ratio of the areas of two squares is 9 : 1 then the ratio of their perimeter is

7th Class Mathematics in 7th Class 11 months ago

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Let the areas of two SQUARE be \[9{{x}^{2}}\] and \[{{x}^{2}}\] respectively. Then the sides of them will be \[\SQRT{9{{x}^{2}}}\]and\[\sqrt{{{x}^{2}}}\]i.e,\[3x\]and\[x\]respectively. Hence, the RATIO of their perimeter \[=\frac{4\times 3x}{4\times x}=3:1\]

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