ALSO parallel to CD \[\{\text{as}\,AB|\,\,|CD\}\] \[4x=\angle A\] (CORRESPONDING angles) \[6x=\angle B\] (Corresponding angles) \[10x=\angle A+\angle B=130{}^\CIRC \] \[x=\frac{130{}^\circ }{10}=13{}^\circ \]

"> ALSO parallel to CD \[\{\text{as}\,AB|\,\,|CD\}\] \[4x=\angle A\] (CORRESPONDING angles) \[6x=\angle B\] (Corresponding angles) \[10x=\angle A+\angle B=130{}^\CIRC \] \[x=\frac{130{}^\circ }{10}=13{}^\circ \]

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In the given figure AB || CD. Then \['x'\] is equal to

7th Class Mathematics in 7th Class . 11 months ago

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Draw a line \[EF|\,\,|AB,\]\[EF\] is ALSO parallel to CD \[\{\text{as}\,AB|\,\,|CD\}\] \[4x=\angle A\] (CORRESPONDING angles) \[6x=\angle B\] (Corresponding angles) \[10x=\angle A+\angle B=130{}^\CIRC \] \[x=\frac{130{}^\circ }{10}=13{}^\circ \]

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