DIAGRAM below, in the isosceles right triangle, the BASE is bisected by the altitude and BD = AD. \[\therefore AD=15\,CM\] AREA\[=\frac{1}{2}\times \]base\[\times \]height         \[=\frac{1}{2}\times 30\times 15=225\,c{{m}^{2}}\]

"> DIAGRAM below, in the isosceles right triangle, the BASE is bisected by the altitude and BD = AD. \[\therefore AD=15\,CM\] AREA\[=\frac{1}{2}\times \]base\[\times \]height         \[=\frac{1}{2}\times 30\times 15=225\,c{{m}^{2}}\]

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The base of an isosceles right triangle is 30 cm. Its area is

7th Class Mathematics in 7th Class 10 months ago

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As shown in the DIAGRAM below, in the isosceles right triangle, the BASE is bisected by the altitude and BD = AD. \[\therefore AD=15\,CM\] AREA\[=\frac{1}{2}\times \]base\[\times \]height         \[=\frac{1}{2}\times 30\times 15=225\,c{{m}^{2}}\]

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