LET the four parts be (a - 3D), (a - d), (a + d) and (a + 3d).
(a - 3d) + (a - d) + (a +d ) + (a + 3d) = 124
a = 31
Also, (a - 3d) (a + 3d) = (a - d) (a + d) - 128
a2 - 9d2 = a2 - d2 - 128
8d2 = 128
d = 4
a = 31, d = 4
So, the four parts are 19, 27, 35, 43. "> LET the four parts be (a - 3D), (a - d), (a + d) and (a + 3d).
(a - 3d) + (a - d) + (a +d ) + (a + 3d) = 124
a = 31
Also, (a - 3d) (a + 3d) = (a - d) (a + d) - 128
a2 - 9d2 = a2 - d2 - 128
8d2 = 128
d = 4
a = 31, d = 4
So, the four parts are 19, 27, 35, 43. ">

Divided 124 into four parts which are in AP such that the product of the first and fourth part is 128 less than the products of the seconds and third part ?

Aptitude Sequences and Series in Aptitude 3 months ago

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LET the four parts be (a - 3D), (a - d), (a + d) and (a + 3d).
(a - 3d) + (a - d) + (a +d ) + (a + 3d) = 124
a = 31
Also, (a - 3d) (a + 3d) = (a - d) (a + d) - 128
a2 - 9d2 = a2 - d2 - 128
8d2 = 128
d = 4
a = 31, d = 4
So, the four parts are 19, 27, 35, 43.

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