I got 80 marks in JEE Mains and 94.9% in intermediate. What will be my JEE rank?

Career Talk Work & Career 2 years ago

0 11 0 0 0 tuteeHUB earn credit +10 pts

5 Star Rating 1 Rating
I got 80 marks in JEE Mains and 94.9% in intermediate. What will be my JEE rank?

Posted on 16 Aug 2022, this text provides information on Work & Career related to Career Talk. Please note that while accuracy is prioritized, the data presented might not be entirely correct or up-to-date. This information is offered for general knowledge and informational purposes only, and should not be considered as a substitute for professional advice.

Take Quiz To Earn Credits!

Turn Your Knowledge into Earnings.

tuteehub_quiz

Answers (11)

Post Answer
profilepic.png
manpreet Tuteehub forum best answer Best Answer 2 years ago
You can find your rank in JEE Mains score card. Please check.
profilepic.png
manpreet 2 years ago
For finding your rank in her Mains, your percentile should be known. So, firstly, provide your percentile. See, there is no weightage of 12 percentage but you should have at least 75% in 12 for eligible for giving JEE advance.
0 views   0 shares

profilepic.png
manpreet 2 years ago
As per as the new rule is concerned there is no need of intermediate of 12 score. According to previous year cut off , your predicted rank will be around 15k
0 views   0 shares

profilepic.png
manpreet 2 years ago
Hello! Please use the college predictor tool by Shiksha. This will help you to predict the college according to your rank/percentile.
0 views   0 shares

profilepic.png
manpreet 2 years ago
. Good Luck.
0 views   0 shares

profilepic.png
manpreet 2 years ago
For calculating your rank, you should consider the percentile provided by NTA. And use the rank formula given in NTA brochure.
0 views   0 shares

No matter what stage you're at in your education or career, TuteeHub will help you reach the next level that you're aiming for. Simply,Choose a subject/topic and get started in self-paced practice sessions to improve your knowledge and scores.