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LoginWhat is the Van’t Hoff Factor for 1 mole of BaCl2, assuming 100% dissociation?
(a) 0.33
(b) 1
(c) 3
(d) 2
I had been asked this question in an internship interview.
This interesting question is from Abnormal Molar Masses topic in section Solutions of Chemistry – Class 12
Chemistry – Class 12 Solutions in Chemistry – Class 12 . 3 years ago
+10 pts
Right answer is (c) 3
Best explanation: VAN’t Hoff Factor can also be WRITTEN as the ratio between the total number of moles of particles after association / DISSOCIATION and the total number of moles of particles before association / dissociation. Since BACL2 COMPLETELY dissociates(into one Ba^2+ and two Cl^– ions), the total number of moles after dissociation is equal to 3. Therefore, the Van’t Hoff Factor for BaCl2 is 3.
Posted on 02 Dec 2021, this text provides information on Chemistry – Class 12 related to Solutions in Chemistry – Class 12. Please note that while accuracy is prioritized, the data presented might not be entirely correct or up-to-date. This information is offered for general knowledge and informational purposes only, and should not be considered as a substitute for professional advice.
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