50 mL of a gaseous hydrocarbon is mixed with excess of oxygen and burnt and cooled to thelaboratory temperature. Thereduction in volume wasfound to be150 mL. The gas is then passed intocaustic potash, when there is a further reduction inthe volume of 150 mL. Provide all thevolumesare measured at the same conditions of temperature and pressure, find out themolecular formula of thehydrocarbon.

Class 10 Chemistry in Class 10 3 years ago

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Solution :Chemical REACTION equation to combustion reaction is
`{:(C_(x)H_(y)+O_(2) to CO_(2)+H_(2)O),("50ML"" 150mL""150mL"):}`
We know volume of gas has same number of moles, at same temperature andpressure
`{:("50 moles"" 150 moles""150 moles"),(C_(x)H_(y)+(x+y/4)O_(2) toxCO_(2) + y/2 H_(2)O),("50 MOLE""150 mole""150 mole"):}`
Given that reduction in volume, when thegases mixture is cooled to the laboratory temperature = 150 ML
`:. y/2 (50) = 150 rArr y = 6`.
and `x (50) = 150 rArr x = 3`
`:.` Hydrocarbon is `C_(3)H_(6)`.

Posted on 04 Dec 2021, this text provides information on Class 10 related to Chemistry in Class 10. Please note that while accuracy is prioritized, the data presented might not be entirely correct or up-to-date. This information is offered for general knowledge and informational purposes only, and should not be considered as a substitute for professional advice.

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