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If in figure, R_1 = 10 Omega,R_2=40 Omega, R_3 = 30 Omega, R_4 = 20 Omega, R_5 = 60 Omega a 12 V battery is connected to the arrangement. Calculate ( a ) the total resistance in the circuit and ( b ) the total current flowing in the circuit.

Class 10 Physics in Class 10 3 years ago

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SOLUTION :( a ) Suppose, we replace the parallel resistors `R_1 and R_2` by an eqUivalent resistor of resistance, R.. Similarly we replace the parallel resistors `R_3,R_4 and R_5`by an eqUivalent single resistor of resistance R". Then using equation of equivalent resistance of parallel combination of resistances,
we have `1/(R.) = 1/10 +1/40 =5/40 , " that is " R. = 8 OMEGA`

Similarly, `1/(R.) = 1/30 + 1/20 + 1/60 + 6/60` , that is,`R.. =1 0Omega`
Thus, the total resistance,R = R. + R.. = `18 Omega`
( b ) To CALCULATE teh current, we use the Ohm.s law, and get
`I = V/R =(12V)/(18Omega) = 0.67 A`.
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Posted on 11 Dec 2021, this text provides information on Class 10 related to Physics in Class 10. Please note that while accuracy is prioritized, the data presented might not be entirely correct or up-to-date. This information is offered for general knowledge and informational purposes only, and should not be considered as a substitute for professional advice.

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