A free sationary Ir^(191) nucleus with excitation energy E=129 keV passes to the ground state, emitting a gamma quantum. Calculate the fractional change of gamma quanta energy due to recoil of the nucleus.

Class 12 Physics in Class 12 . 3 years ago

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Solution :With recoil NEGLECTED, the `gamma` quantum will have `129keV` enrgy. To a first APPROXIMATION, its momenturm will be `129keV//c` and the energy of recoil will be
`((0.129)^(2))/(2xx191xx931)MeV= 4.18xx10^(-8)MeV`
In the next approximation we therefore WRITE `E_(gamma)overset~-.129-8.2xx10^(-8)MeV`
Therefore `(deltaE)/(E_(gamma))=3.63xx10^(-7)`

Posted on 11 Dec 2021, this text provides information on Class 12 related to Physics in Class 12. Please note that while accuracy is prioritized, the data presented might not be entirely correct or up-to-date. This information is offered for general knowledge and informational purposes only, and should not be considered as a substitute for professional advice.

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