A solid cylinder of mass M and radius R rolls without slipping down an inclined plane of length L and height h. What is the speed of its centre of mass when the cylinder reaches its bottom ?

Class 12 Physics in Class 12 3 years ago

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`SQRT(2gh)`
`sqrt(3/4gh)`
`sqrt(4/3gh)`
`sqrt(4gh)`

SOLUTION :Potential energy of the SOLID cylinder at HEIGHT h = Mgh
K.E. of centre of mass when reached at bottom
`=1/2Mv^(2)+1/2Iomega^(2)=1/2Mv^(2)+1/2Mk^(2)v^(2)//R^(2)`
`=1/2Mv^(2)(1+(k^(2))/(R^(2)))`
For a solid cylinder, `(k^(2))/(R^(2))=1/2therefore` K.E.`=3/4Mv^(2)`
`thereforeMgh=3/4Mv^(2)rArrv=sqrt(4/3gh)`

Posted on 11 Dec 2021, this text provides information on Class 12 related to Physics in Class 12. Please note that while accuracy is prioritized, the data presented might not be entirely correct or up-to-date. This information is offered for general knowledge and informational purposes only, and should not be considered as a substitute for professional advice.

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