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LoginCalculate the number of electrons, protons and neutrons present in 24 grams of ""_(12)Mg^(24)and ""_(12)Mg^(26).
Class 12 Physics in Class 12 . 3 years ago
+10 pts
`therefore` 24 g of Mg has `12 xx 6.023 xx 10^(23)` protons `=72.2 xx 10^(23)`
`therefore 24`g of Mg has `12 xx 6.023 xx 10^(23)` electrons
`=72.2 xx 10^(23)`
`therefore 24G` of Mg has `12 xx 6.023 xx 10^(23)` neutrons
`=72.2 xx 10^(23)`
For `""_(12)Mg^(26)`
26 g of Mg has `6.023 xx 10^(23)` atoms
1g of Mg has `(6.023 xx 10^(23))/26 xx 24` atoms
`=5.56 xx 10^(23)` atoms
`therefore` Totalnumber of electrons in 24 g of `""_(12)Mg^(26) = 12 xx 5.56 xx 10^(23) = 66,72 xx 10^(23`
`therefore` Total NUMBER of proton in 24 g of `""_(12)Mg^(26)`
`=66.72 xx 10^(23)`
`therefore` total number of proton in 24 g of `""_(12)Mg^(26) = 66.72 xx 10^(23)`
Total number of neutrons in 24 g of `""_(12)Mg^(26)`
`=14 xx 5.56 xx 10^(23) = 77.84 xx 10^(23)`
Posted on 11 Dec 2021, this text provides information on Class 12 related to Physics in Class 12. Please note that while accuracy is prioritized, the data presented might not be entirely correct or up-to-date. This information is offered for general knowledge and informational purposes only, and should not be considered as a substitute for professional advice.
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