Consider a coin of Question 20. It is electrically neutral and contains equal amounts of positive and negative charge of magnitude 34.8 kC. Suppose that these equal charges were concentrated in two point charges separated by:
(i) 1 cm (-1/2) xx displacement of the one paisa coin)
(ii) 100 m (-length of a long building)
(iii) 10^(6) m (radius of the earth).
Find the force on each such point charge in each of the three cases. What do you conclude from these results ?

Class 12 Physics in Class 12 3 years ago

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Solution :Here, `r_(1) = 1 cm = 10^(-2)` m
`r_(2) = 100 m`
`r_(3) = 10^(6) m`
`1/(4pi epsilon_(0)) = k = 9 xx 10^(9)`
(i) `F_(1) = (k|q|^(2))/(r_(1)^(2)) =(9 xx 10^(9) xx (3.48 xx 10^(4))^(2))/(10^(-2))^(2)`
`=1.09 xx 10^(23)` N
(ii) `F_(2) = (k|q|^(2))/r_(2)^(2) = (9 xx 10^(9) xx (3.48 xx 10^(4))^(2))/(100)^(2) = 1.09 xx 10^(15)` N
(iii) `F_(3) = (k|q|^(2))/r_(3)^(2) = (9 xx 10^(9) xx (3.48 xx 10^(4))^(2))/(10^(6))^(2)`
`=1.09 xx 10^(7)` N
Conclusion : Here, the force between charges is MUCH more hence, it is difficult to disturb electrical neutrality of matter.

Posted on 11 Dec 2021, this text provides information on Class 12 related to Physics in Class 12. Please note that while accuracy is prioritized, the data presented might not be entirely correct or up-to-date. This information is offered for general knowledge and informational purposes only, and should not be considered as a substitute for professional advice.

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