How high must be the kinetic energy of a proton striking another, stationary, proton for their combined kinetic energy in the frame of the centre of inertia to be equal to the total kinetic energy of two protons moving toward each other with individual kinetic energies T=25.0 GeV?

Class 12 Physics in Class 12 3 years ago

  399   0   0   0   0 tuteeHUB earn credit +10 pts

5 Star Rating 1 Rating

Solution :Let `T^'=` KINETIC ENERGY of a proton striking another stationary particle of the same rest mass. Then, COMBINED kinetic energy in the CM FRAME
`=2m_0c^2(sqrt(1+(T^')/(2m_0c^2)-1))=2T`, `((T)/(m_0c^2)+1)^2=(T^')/(2m_0c^2)`
`(T^')/(2m_0c^2)=(T(2m_0c^2+T))/(m_0^2c^4)`, `T^'=(2T(T+2m_0c^2))/(m_0c^2)`

Posted on 11 Dec 2021, this text provides information on Class 12 related to Physics in Class 12. Please note that while accuracy is prioritized, the data presented might not be entirely correct or up-to-date. This information is offered for general knowledge and informational purposes only, and should not be considered as a substitute for professional advice.

Take Quiz To Earn Credits!

Turn Your Knowledge into Earnings.

tuteehub_quiz

Tuteehub forum answer Answers

Post Answer

No matter what stage you're at in your education or career, TuteeHub will help you reach the next level that you're aiming for. Simply,Choose a subject/topic and get started in self-paced practice sessions to improve your knowledge and scores.