Clarification: non-relativistic fine structure of a one-electron atom

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Posted on 16 Aug 2022, this text provides information on Syllabus Queries related to Course Queries. Please note that while accuracy is prioritized, the data presented might not be entirely correct or up-to-date. This information is offered for general knowledge and informational purposes only, and should not be considered as a substitute for professional advice.

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manpreet Tuteehub forum best answer Best Answer 2 years ago

The fine structure energy shift (in the non-relativistic limit) for a single-electron atom due to spin-orbit coupling is given by

ΔElj(j+1)l(l+1)s(s+1)2l(l+12)(l+1)ΔEl∝j(j+1)−l(l+1)−s(s+1)2l(l+12)(l+1)

which does not apply when l=0l=0 (as it would be singular). ll is the orbital angular momentum of the electron, ss is its spin angular momentum, and jj is the total angular momentum given by |ls|jl+s|l−s|≤j≤l+s in integer steps (j=l+s)(j=l+s).

 

For the example of hydrogen in the n=2n=2 level:

Am I right in thinking there is not supposed to be any shift for the l=0l=0 s-orbital (j=12j=12)? We can't calculate anything using the formula above in this case, but for the 

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