Convergence of integral in complex analysis textbook

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manpreet Tuteehub forum best answer Best Answer 2 years ago

 

In my complex analysis textbook it states that the following integral converges

1tα1etdt∫1∞tα−1e−tdt

where αα is some real number such that α>1α>1

Also, it seems that ttα1ett→tα−1e−t is taken to be a real valued function of a real variable.

This integral appears in a demonstration of using a certain theorem. In the statement of the theorem, it states

"... and there exists a continuous non-negative h:[0,)[0,)h:[0,∞)→[0,∞) such that the integral 0h(t)dt∫0∞h(t)dtconverges and ..." (Translated from Hebrew).

Is there more than one definition of convergence that could be applied to this? I do not think that my textbook previously defined such an (improper?) integral, so it may be a definition from "Calculus II" (Israeli Syllabus)

In the "most basic" or "most likely" sense of convergence, how can it be shown that this integral does in href="https://forum.tuteehub.com/tag/fact">fact converge?

Thanks!

(Note: I tagged the question with "improper-integrals", but this should not be taken to imply that this it is assumed that this is the definition the author meant)

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manpreet 2 years ago

For each AAA0tα1etdt∫0Atα−1e−tdt exists by continuity of the integrand. If we show that BAtα1etdt0∫ABtα−1e−tdt→0as B>AB>A→∞ we can conclude that the improper integral exists. To show this, note that et2tkk!et2≥tkk!for any positive integer kk hence tα1et

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