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Course Queries Syllabus Queries 2 years ago
Posted on 16 Aug 2022, this text provides information on Syllabus Queries related to Course Queries. Please note that while accuracy is prioritized, the data presented might not be entirely correct or up-to-date. This information is offered for general knowledge and informational purposes only, and should not be considered as a substitute for professional advice.
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In my complex analysis textbook it states that the following integral converges
∫∞1tα−1e−tdt∫1∞tα−1e−tdt
where αα is some real number such that α>1α>1
Also, it seems that t→tα−1e−tt→tα−1e−t is taken to be a real valued function of a real variable.
This integral appears in a demonstration of using a certain theorem. In the statement of the theorem, it states
"... and there exists a continuous non-negative h:[0,∞)→[0,∞)h:[0,∞)→[0,∞) such that the integral ∫∞0h(t)dt∫0∞h(t)dtconverges and ..." (Translated from Hebrew).
Is there more than one definition of convergence that could be applied to this? I do not think that my textbook previously defined such an (improper?) integral, so it may be a definition from "Calculus II" (Israeli Syllabus)
In the "most basic" or "most likely" sense of convergence, how can it be shown that this integral does in href="https://forum.tuteehub.com/tag/fact">fact converge?
Thanks!
(Note: I tagged the question with "improper-integrals", but this should not be taken to imply that this it is assumed that this is the definition the author meant)
For each AA, ∫A0tα−1e−tdt∫0Atα−1e−tdt exists by continuity of the integrand. If we show that ∫BAtα−1e−tdt→0∫ABtα−1e−tdt→0as B>A→∞B>A→∞ we can conclude that the improper integral exists. To show this, note that et2≥tkk!et2≥tkk!for any positive integer kk hence tα−1e−t REPLY 0 views 0 likes 0 shares Facebook Twitter Linked In WhatsApp
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