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manpreet
Best Answer
2 years ago
Question: If p2qp2q and q2pq2p are the roots of the equation 2x2+7x−4=02x2+7x−4=0, find the equation whose roots are pp and qq(p+qp+q is real).
My attempt: The required equation is x2−(p+q)x+pqx2−(p+q)x+pq
(p2q)(q2p)=−42(p2q)(q2p)=−42
pq=−2pq=−2