listfragment overlapping my main drawer

manpreet Best Answer 3 years ago

im new in android im creating an app and i have a problem with a listfragment, because the list its showing but its overlapping the title bar(i had to add margin top to change that), and also im using a drawer and when im trying to open the list it shows over the options drawer too, letme paste you the code and the image so you can understan more:

The xml code:

    xml version="1.0" encoding="utf-8"?>
 xmlns:android="http://schemas.android.com/apk/res/android"
    android:https://forum.tuteehub.com/tag/orientation">orientation="vertical" android:layout_width="match_parent"
    android:layout_height="match_parent"
    android:weightSum="1">

    
        android:layout_width="match_parent"
        android:layout_height="420dp"
        android:id="@android:id/https://forum.tuteehub.com/tag/list">list"
        android:layout_weight="0.82"
        android:layout_marginTop="60dp" />

The https://forum.tuteehub.com/tag/list">listFregment code:

  public class FragmentoPrincipalChofer extends ListFragment {
    private List<ParseObject> mViaje;
    private ListView mLista;

    public View onCreateView(LayoutInflater inflater, ViewGroup container,
                             Bundle savedInstanceState) {



        View x = inflater.inflate(R.layout.fragmento_principal_chofer, container, false);
        mLista = (ListView)x.findViewById(android.R.id.https://forum.tuteehub.com/tag/list">list);
        return x;

    }

    @Override
    public void onResume() {
        super.onResume();

        //obtener pedido de taxi
       ParseQuery<ParseObject> query = ParseQuery.getQuery("Viaje");
        query.whereEqualTo("chofer", "prueba3");
        query.addDescendingOrder("createdAt");
        query.findInBackground(new FindCallback<ParseObject>() {
            public void done(List<ParseObject> viajes, com.parse.ParseException e) {
                if (e == null) {
                    mViaje=viajes;
                    String[] nombreUsuarios = new String[mViaje.size()];
                    int i=0;
                    for (ParseObject viaje : mViaje){

                        nombreUsuarios[i] = viaje.getString("cliente");
                        i++;
                    
                                                

                                                                                                        
                                                    
                                                
                                                

                                                    

                                                        
                                                            0
                                                            views 

                                                            0
                                                                likes 
                                                            
                                                            

                                                            0
                                                            shares
                                                            


    

         Facebook
        
         Twitter
        
        
         Linked In 
        
          WhatsApp