php $_GET and undefined index

manpreet Best Answer 3 years ago

A new problem has arisen for me as I tried to run my script on a different PHP Server.

ON my old server the following code appears to work fine - even when no s parameter is declared.

php
 if ($_GET['s'] == 'jwshxnsyllabus')
echo "syllabus', '../syllabi/jwshxnporsyllabus.xml',         '../bibliographies/jwshxnbibliography_')\">";
if ($_GET['s'] == 'aquinas')
echo "syllabus', '../syllabi/AquinasSyllabus.xml')\">"; 
 if ($_GET['s'] == 'POP2')
echo "";
elseif ($_GET['s'] == null)
echo ""
?>

But now, on a my local server on my local machine (XAMPP - Apache) I get the following error when no value for s is defined.

Notice: Undefined index: s in C:\xampp\htdocs\teaching\index.php on line 43
Notice: Undefined index: s in C:\xampp\htdocs\teaching\index.php on line 45
Notice: Undefined index: s in C:\xampp\htdocs\teaching\index.php on line 47
Notice: Undefined index: s in C:\xampp\htdocs\teaching\index.php on line 49

What I want to happen for the script to call certain javascript functions if a value is declared for s, but if nothing is declared i would like the page to load normally.

Can you help me?

manpreet 3 years ago

if (isset($_GET['s'])) {
    if ($_GET['s'] == 'jwshxnsyllabus')
        echo "";
    else if ($_GET['s'] == 'aquinas')
        echo ""; 
    else if ($_GET['s'] == 'POP2')
        echo "";
} else {
    echo "";
}

switch ((isset($_GET['s']) ? $_GET['s'] : '')) {
    case 'jwshxnsyllabus':
        echo "";
        break;
    case 'aquinas':
        echo "";
        break;
    case 'POP2':
        echo "";
        break;
    default:
        echo "";
        break;
}