The floor function's relationship with odd and even functions

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manpreet Tuteehub forum best answer Best Answer 2 years ago

Question

Suppose f:RRf:ℜ→ℜ is a real valued function defined on the whole real line. For each a) and b) determine if the statement is correct and justify your answer.

a) If f(x)f(x) is even then g(x)=f(x)g(x)=⌊f(x)⌋ even.

b) If f(x)f(x) is odd then g(x)=f(x)g(x)=⌊f(x)⌋ odd.


Things I know

I know that the ref="https://forum.tuteehub.com/tag/floor">floor ref="https://forum.tuteehub.com/tag/function">function is the greatest integer less than the value x.

f(x)=f(x)f(x)=f(−x) if f(x)f(x) is even and the graphs are symmetrical about y=0

f(x)=f(x)f(x)=−f(−x) if f(x)f(x) is odd

I have tried to think of a way, but with the knowledge I dont know how to come to the conclusion if the statements are correct and to justify. But my knowledge is up to date with the ref="https://forum.tuteehub.com/tag/school">school syllabus (what we have been taught already). How do I do this?

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manpreet 2 years ago

b) is incorrect. The easiest counter example is taking f(x)=xf(x)=x. Booldy's counter example is correct too because if f(x)=sinxf(x)=sin⁡x then g(x)=sin(x)=sinxg(x)=⌊sin⁡(−x)⌋=⌊−sin⁡x⌋ but nothing ensures that sinx=sinx⌊−sin⁡x⌋=−⌊sin⁡x⌋. Take x=π4x=π4 to be convinced.

For a) just use the definition you have. Let xRx∈R.ff is even so f(x)=f(x)f(−x)=f(x). Now use this while calculating g(x)g(−x).


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