If you know the expansion of (a+b)n, it follows that the expansion of (a+b)n+1=(a+b)(a+b)n=a(a+b)n+b(a+b)n can be found by distributing term by term and collecting coefficients. This is the type of reasoning you should use when doing inductive proofs.
manpreet
Best Answer
2 years ago
I'm following Cambrige mathematics syllabus, from the list of contents of what should be learned:
I know what it is, but I'm not sure of what should be proved here. The first thing that comes to mind is the idea of proving it it for n+1n+1, but I thought about writing:
(a+b)n(a+b)n
(a+b)n+1(a+b)n+1
But I am missing what premise I should prove. I guess that the proof involves the nature of the coefficients of the expansion of (a+b)n(a+b)n but from here, I have no idea on how to proceed. Can you help me?
Edit: I guess I've made some progress. First I evaluated
Then I've evaluated it with the summation form
And confirmed that it's equal to 11 (I guess this is the base step).
The I did the same for
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