GIVEN:The ratio of the TWO numbers is 17 : 28.Concept USED:Ratio concept used.Calculation:Let the smaller number be xAnd the larger number be ySo, x/y = 17/28 ⇒ 28x = 17y ----(i)When 6 is added to the smaller number, the smaller number becomes = x + 6SO, the new ratio becomes:(x + 6)/y = 13/20 ⇒ 20 × (x + 6) = 13y⇒ 20x + 120 = 13y⇒ x = (13y – 120)/20 ----(ii)We substitute the value of x from equation(ii) into equation(i), to get:28 × [(13y – 120)/20]= 17y⇒ 28 × (0.65y – 6) = 17y⇒ y = 140∴ The value of the larger number is 140.(17x + 6) : 28x = 13 : 20⇒ (17x + 6)/28x = 13/20⇒ 20(17x + 6) = 13(28x)⇒ 340x + 120 = 364x⇒ 120 = 24x⇒ x = 120/24 = 5Larger number = 28x = 28 × 5 = 140∴ The value of the larger number is 140. "> GIVEN:The ratio of the TWO numbers is 17 : 28.Concept USED:Ratio concept used.Calculation:Let the smaller number be xAnd the larger number be ySo, x/y = 17/28 ⇒ 28x = 17y ----(i)When 6 is added to the smaller number, the smaller number becomes = x + 6SO, the new ratio becomes:(x + 6)/y = 13/20 ⇒ 20 × (x + 6) = 13y⇒ 20x + 120 = 13y⇒ x = (13y – 120)/20 ----(ii)We substitute the value of x from equation(ii) into equation(i), to get:28 × [(13y – 120)/20]= 17y⇒ 28 × (0.65y – 6) = 17y⇒ y = 140∴ The value of the larger number is 140.(17x + 6) : 28x = 13 : 20⇒ (17x + 6)/28x = 13/20⇒ 20(17x + 6) = 13(28x)⇒ 340x + 120 = 364x⇒ 120 = 24x⇒ x = 120/24 = 5Larger number = 28x = 28 × 5 = 140∴ The value of the larger number is 140. ">

The ratio of the two numbers is 17 : 28. If 6 is added to the smaller number, then the ratio changes to 13 : 20. What is the value of a larger number?

Current Affairs General Awareness in Current Affairs 8 months ago

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GIVEN:The ratio of the TWO numbers is 17 : 28.Concept USED:Ratio concept used.Calculation:Let the smaller number be xAnd the larger number be ySo, x/y = 17/28 ⇒ 28x = 17y ----(i)When 6 is added to the smaller number, the smaller number becomes = x + 6SO, the new ratio becomes:(x + 6)/y = 13/20 ⇒ 20 × (x + 6) = 13y⇒ 20x + 120 = 13y⇒ x = (13y – 120)/20 ----(ii)We substitute the value of x from equation(ii) into equation(i), to get:28 × [(13y – 120)/20]= 17y⇒ 28 × (0.65y – 6) = 17y⇒ y = 140∴ The value of the larger number is 140.(17x + 6) : 28x = 13 : 20⇒ (17x + 6)/28x = 13/20⇒ 20(17x + 6) = 13(28x)⇒ 340x + 120 = 364x⇒ 120 = 24x⇒ x = 120/24 = 5Larger number = 28x = 28 × 5 = 140∴ The value of the larger number is 140.

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