GIVEN:Price is depreciated by 20% each yearCalculation:LET be assume the original price is X⇒ After 3 years price = x × 4/5 × 4/5 × 4/5 = (64/125) × x⇒ After 4 years price =x × 4/5 × 4/5 × 4/5 × 4/5 = (256/625) × x⇒ {(64/125) - (256/625)} × x = 3328⇒ 0.1024 × x = 3328⇒ x = 32500⇒ For second-year price = 32500 × 4/5 × 4/5 = 20800∴ The required RESULT will be 20800. "> GIVEN:Price is depreciated by 20% each yearCalculation:LET be assume the original price is X⇒ After 3 years price = x × 4/5 × 4/5 × 4/5 = (64/125) × x⇒ After 4 years price =x × 4/5 × 4/5 × 4/5 × 4/5 = (256/625) × x⇒ {(64/125) - (256/625)} × x = 3328⇒ 0.1024 × x = 3328⇒ x = 32500⇒ For second-year price = 32500 × 4/5 × 4/5 = 20800∴ The required RESULT will be 20800. ">

The value of an equipment depreciates by 20% each year. If the difference between the prices at the end of 3rd and 4th year is Rs. 3,328, then what is the price of the equipment at the end of the second year?

Current Affairs General Awareness in Current Affairs 10 months ago

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GIVEN:Price is depreciated by 20% each yearCalculation:LET be assume the original price is X⇒ After 3 years price = x × 4/5 × 4/5 × 4/5 = (64/125) × x⇒ After 4 years price =x × 4/5 × 4/5 × 4/5 × 4/5 = (256/625) × x⇒ {(64/125) - (256/625)} × x = 3328⇒ 0.1024 × x = 3328⇒ x = 32500⇒ For second-year price = 32500 × 4/5 × 4/5 = 20800∴ The required RESULT will be 20800.

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