FRAC{{\pi {d^4}}}{{32}} = \frac{\pi }{{32}}\left[ {d_0^4 - d_i^4} \RIGHT]\)\(\Rightarrow {d_o} > d \Rightarrow {r_0} > r\)Now, angle of TWIST\(\theta = \frac{{TL}}{{GJ}}\)∴ θS = θH ----(1) (∵ T, L, G, J all are same for solid and Hollow shaft)\(\tau = \frac{{TR}}{J}\)\(\Rightarrow {\tau _{max}}\;for\;solid\;shaft = \frac{T}{J}.r\)\({\tau _{max}}\;for\;hollow\;shaft = \frac{T}{J}.{r_0}\)∵ r0 > r∴ (τmax)H > (τmax)S ----(2)Hence from (1) and (2) we can see that the correct option is d.