DIVISIBLE by 3, SUM of the digits of that number must be divisible by 3⇒ Sum of the digits of number 267Y2 = 2 + 6 + 7 + Y + 2 = 17 + YThe minimum value of Y that to be added to 17 + Y, so that it is divisible by Y is 1⇒ 17 + Y = 17 + 1 = 18, which is divisible by 3∴ The minimum value of Y is 1

"> DIVISIBLE by 3, SUM of the digits of that number must be divisible by 3⇒ Sum of the digits of number 267Y2 = 2 + 6 + 7 + Y + 2 = 17 + YThe minimum value of Y that to be added to 17 + Y, so that it is divisible by Y is 1⇒ 17 + Y = 17 + 1 = 18, which is divisible by 3∴ The minimum value of Y is 1

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What is the minimum value of ‘Y’ for which 267Y2 is divisible by 3?

Current Affairs General Awareness in Current Affairs . 8 months ago

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From the given data,For a number to be DIVISIBLE by 3, SUM of the digits of that number must be divisible by 3⇒ Sum of the digits of number 267Y2 = 2 + 6 + 7 + Y + 2 = 17 + YThe minimum value of Y that to be added to 17 + Y, so that it is divisible by Y is 1⇒ 17 + Y = 17 + 1 = 18, which is divisible by 3∴ The minimum value of Y is 1

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Posted on 10 Nov 2024, this text provides information on Current Affairs related to General Awareness in Current Affairs. Please note that while accuracy is prioritized, the data presented might not be entirely correct or up-to-date. This information is offered for general knowledge and informational purposes only, and should not be considered as a substitute for professional advice.

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