DIVIDED by 4, 5, 6, 7, and 9, then the remainder is 1Calculation:LCM of 4, 5, 6, 7, and 9⇒ 3 × 2 × 2 × 5 × 1 × 7 × 3⇒ 1260We need greatest 4 digit NUMBER, Which is divisible by 1,260Greatest 4 digit number is 9,999When we divide 9,999 by 1260 the remainder is,⇒ 9,999/1260 = \(7\frac{{1179}}{{1260}}\)Remainder is 1179,Greatest 4 digit number which is divisible by 1260 is,⇒ 9,999 – 1,179⇒ 8820When divided by 4, 5, 6, 7, and 9 the remainder is 1,⇒ The actual number is 8,820 + 1⇒ The actual number is 8,821The sum of digits of a number is 8 + 8 + 2 + 1 = 19∴ The sum of digits is 19.

"> DIVIDED by 4, 5, 6, 7, and 9, then the remainder is 1Calculation:LCM of 4, 5, 6, 7, and 9⇒ 3 × 2 × 2 × 5 × 1 × 7 × 3⇒ 1260We need greatest 4 digit NUMBER, Which is divisible by 1,260Greatest 4 digit number is 9,999When we divide 9,999 by 1260 the remainder is,⇒ 9,999/1260 = \(7\frac{{1179}}{{1260}}\)Remainder is 1179,Greatest 4 digit number which is divisible by 1260 is,⇒ 9,999 – 1,179⇒ 8820When divided by 4, 5, 6, 7, and 9 the remainder is 1,⇒ The actual number is 8,820 + 1⇒ The actual number is 8,821The sum of digits of a number is 8 + 8 + 2 + 1 = 19∴ The sum of digits is 19.

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Let x be the greatest 4-digit number which when divided by 4, 5, 6, 7 and 9, the remainder in each case is 1. What is the sum of the digits of x?

Digital Circuits Number System in Digital Circuits . 6 months ago

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Given:x is DIVIDED by 4, 5, 6, 7, and 9, then the remainder is 1Calculation:LCM of 4, 5, 6, 7, and 9⇒ 3 × 2 × 2 × 5 × 1 × 7 × 3⇒ 1260We need greatest 4 digit NUMBER, Which is divisible by 1,260Greatest 4 digit number is 9,999When we divide 9,999 by 1260 the remainder is,⇒ 9,999/1260 = \(7\frac{{1179}}{{1260}}\)Remainder is 1179,Greatest 4 digit number which is divisible by 1260 is,⇒ 9,999 – 1,179⇒ 8820When divided by 4, 5, 6, 7, and 9 the remainder is 1,⇒ The actual number is 8,820 + 1⇒ The actual number is 8,821The sum of digits of a number is 8 + 8 + 2 + 1 = 19∴ The sum of digits is 19.

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