VALUE is 0 because it can not negative ⇒ a = b = c = d ⇒ 4A = 30, So a = 7.5 but according to question it can not be DECIMAL ⇒ Let we assume it is 7 or 8⇒ For 7 sum of all digit = 7 × 4 = 28⇒ It falls SHORT of 30 by 2 hence number are 7, 7, 8, 8⇒ For 8 sum of all digit = 8 × 4 = 32⇒ It exceeds 30 by 2 hence NUMBERS 8, 8, 7, 7.⇒ In both cases, the result will be 2∴ The required result will be 2.

"> VALUE is 0 because it can not negative ⇒ a = b = c = d ⇒ 4A = 30, So a = 7.5 but according to question it can not be DECIMAL ⇒ Let we assume it is 7 or 8⇒ For 7 sum of all digit = 7 × 4 = 28⇒ It falls SHORT of 30 by 2 hence number are 7, 7, 8, 8⇒ For 8 sum of all digit = 8 × 4 = 32⇒ It exceeds 30 by 2 hence NUMBERS 8, 8, 7, 7.⇒ In both cases, the result will be 2∴ The required result will be 2.

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If a, b, c, and d are integers such that a + b + c + d = 30, then the minimum possible value of (a - b)2 + (a - c)2 + (a - d)2 is

Digital Circuits Number System in Digital Circuits . 6 months ago

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Calculation:Let the minimum possible VALUE is 0 because it can not negative ⇒ a = b = c = d ⇒ 4A = 30, So a = 7.5 but according to question it can not be DECIMAL ⇒ Let we assume it is 7 or 8⇒ For 7 sum of all digit = 7 × 4 = 28⇒ It falls SHORT of 30 by 2 hence number are 7, 7, 8, 8⇒ For 8 sum of all digit = 8 × 4 = 32⇒ It exceeds 30 by 2 hence NUMBERS 8, 8, 7, 7.⇒ In both cases, the result will be 2∴ The required result will be 2.

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