GIVEN:x + 2 is a factor of x2 + ax + 8Concept Used:If p(x) be a function and (x - a) be a factor of p(x) then, p(a) = 0CalculationLet, p(x) = x2 + ax + 8x + 2 is factor of p(x)⇒ x + 2 = 0 ⇒ x = -2Then by factor theorem p(- 2) = 0 ⇒ p(x) = x2 + ax + 8 ⇒ p(-2) = (-2)2 - 2a + 8⇒ 4 - 2a + 8 = 0 ⇒ 12 - 2a = 0 ⇒ 2a = 12 ⇒ a = 6 ∴ The required ANSWER is a = 6