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Why can I not move unique_ptr from a set to a function argument using an iterator?

Digital Marketing Facebook Marketing API 2 years ago

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_x000D_ _x000D_ I have a set of unique_ptr instances and want to pass all of them as an argument to a function. Example demonstrated by below code. #include #include #include using std::set; using std::unique_ptr; using std::vector; void doStuff(unique_ptr ptr) { // doing stuff... } int main() { vector> ptrVector; set> ptrSet; for (auto cur = ptrVector.begin(); cur != ptrVector.end(); cur++) { doStuff(std::move(*cur)); } for (auto cur = ptrSet.begin(); cur != ptrSet.end(); cur++) { doStuff(std::move(*cur)); } return 0; } This results in the following compiler error (GCC 4.8.1): uptrfncall.cpp: In function ‘int main()’: uptrfncall.cpp:27:25: error: use of deleted function ‘std::unique_ptr::unique_ptr(const std::unique_ptr&) [with _Tp = int; _Dp = std::default_delete]’ doStuff(std::move(*cur)); // line 25, compiler error ^ In file included from /usr/include/c++/4.8/memory:81:0, from uptrfncall.cpp:1: /usr/include/c++/4.8/bits/unique_ptr.h:273:7: error: declared here unique_ptr(const unique_ptr&) = delete; ^ uptrfncall.cpp:9:10: error: initializing argument 1 of ‘void doStuff(std::unique_ptr)’ void doStuff(unique_ptr ptr) ^ Note that it works flawlessly for the vector but not for the set. As the set is not const, the begin() call should not return a const_iterator so it should be possible to move the values when dereferencing the iterator. Why does this not compile?
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Posted on 16 Aug 2022, this text provides information on Facebook Marketing API related to Digital Marketing. Please note that while accuracy is prioritized, the data presented might not be entirely correct or up-to-date. This information is offered for general knowledge and informational purposes only, and should not be considered as a substitute for professional advice.

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manpreet Tuteehub forum best answer Best Answer 2 years ago
_x000D_ The set may not be const, but the elements within it are. You cannot modify a set's elements, as it wouldn't be able to guarantee it's maintaining its invariants.
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