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Why can I not move unique_ptr from a set to a function argument using an iterator?

Digital Marketing Facebook Marketing API 3 years ago

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_x000D_ _x000D_ I have a set of unique_ptr instances and want to pass all of them as an argument to a function. Example demonstrated by below code. #include #include #include using std::set; using std::unique_ptr; using std::vector; void doStuff(unique_ptr ptr) { // doing stuff... } int main() { vector> ptrVector; set> ptrSet; for (auto cur = ptrVector.begin(); cur != ptrVector.end(); cur++) { doStuff(std::move(*cur)); } for (auto cur = ptrSet.begin(); cur != ptrSet.end(); cur++) { doStuff(std::move(*cur)); } return 0; } This results in the following compiler error (GCC 4.8.1): uptrfncall.cpp: In function ‘int main()’: uptrfncall.cpp:27:25: error: use of deleted function ‘std::unique_ptr::unique_ptr(const std::unique_ptr&) [with _Tp = int; _Dp = std::default_delete]’ doStuff(std::move(*cur)); // line 25, compiler error ^ In file included from /usr/include/c++/4.8/memory:81:0, from uptrfncall.cpp:1: /usr/include/c++/4.8/bits/unique_ptr.h:273:7: error: declared here unique_ptr(const unique_ptr&) = delete; ^ uptrfncall.cpp:9:10: error: initializing argument 1 of ‘void doStuff(std::unique_ptr)’ void doStuff(unique_ptr ptr) ^ Note that it works flawlessly for the vector but not for the set. As the set is not const, the begin() call should not return a const_iterator so it should be possible to move the values when dereferencing the iterator. Why does this not compile?
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manpreet Tuteehub forum best answer Best Answer 3 years ago
_x000D_ The set may not be const, but the elements within it are. You cannot modify a set's elements, as it wouldn't be able to guarantee it's maintaining its invariants.
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