AMMETER = average value of given wave formTime period = 2 msLet consider the WAVEFORM for one TIME periodAverage value \(\FRAC{1}{T}\mathop \smallint \limits_0^T i\left( t \right)\;dt\)\(= \frac{1}{{2 \times {{10}^{ - 3}}}}\left[ {\mathop \smallint \limits_0^{1 \times {{10}^{ - 3}}} tdt + \mathop \smallint \limits_{1 \times {{10}^{ - 3}}}^{2 \times {{10}^{ - 3}}} - 1dt} \right]\)\(= \frac{1}{{2 \times {{10}^{ - 3}}}}\left[ {\frac{{1 \times {{10}^{ - 3}}}}{2} + \left( { - 1} \right)\left( {2 - 1} \right)\left( {{{10}^{ - 3}}} \right)} \right]\)\(= \frac{1}{2}\left[ {\frac{1}{2} - 1} \right] = \frac{{ - 1}}{4}A =- 0.25\;A\)

"> AMMETER = average value of given wave formTime period = 2 msLet consider the WAVEFORM for one TIME periodAverage value \(\FRAC{1}{T}\mathop \smallint \limits_0^T i\left( t \right)\;dt\)\(= \frac{1}{{2 \times {{10}^{ - 3}}}}\left[ {\mathop \smallint \limits_0^{1 \times {{10}^{ - 3}}} tdt + \mathop \smallint \limits_{1 \times {{10}^{ - 3}}}^{2 \times {{10}^{ - 3}}} - 1dt} \right]\)\(= \frac{1}{{2 \times {{10}^{ - 3}}}}\left[ {\frac{{1 \times {{10}^{ - 3}}}}{2} + \left( { - 1} \right)\left( {2 - 1} \right)\left( {{{10}^{ - 3}}} \right)} \right]\)\(= \frac{1}{2}\left[ {\frac{1}{2} - 1} \right] = \frac{{ - 1}}{4}A =- 0.25\;A\)

">

A current waveform, i(t), shown in the figure, is passed through a Permanent Magnet Moving Coil (PMMC) type ammeter. The reading of the ammeter up to two decimal places is

Electrical Engineering Indicating Instruments in Electrical Engineering . 7 months ago

  1.52K   0   0   0   0 tuteeHUB earn credit +10 pts

5 Star Rating 1 Rating

PMMC instrument reads average value, So the value of AMMETER = average value of given wave formTime period = 2 msLet consider the WAVEFORM for one TIME periodAverage value \(\FRAC{1}{T}\mathop \smallint \limits_0^T i\left( t \right)\;dt\)\(= \frac{1}{{2 \times {{10}^{ - 3}}}}\left[ {\mathop \smallint \limits_0^{1 \times {{10}^{ - 3}}} tdt + \mathop \smallint \limits_{1 \times {{10}^{ - 3}}}^{2 \times {{10}^{ - 3}}} - 1dt} \right]\)\(= \frac{1}{{2 \times {{10}^{ - 3}}}}\left[ {\frac{{1 \times {{10}^{ - 3}}}}{2} + \left( { - 1} \right)\left( {2 - 1} \right)\left( {{{10}^{ - 3}}} \right)} \right]\)\(= \frac{1}{2}\left[ {\frac{1}{2} - 1} \right] = \frac{{ - 1}}{4}A =- 0.25\;A\)

Posted on 12 Nov 2024, this text provides information on Electrical Engineering related to Indicating Instruments in Electrical Engineering. Please note that while accuracy is prioritized, the data presented might not be entirely correct or up-to-date. This information is offered for general knowledge and informational purposes only, and should not be considered as a substitute for professional advice.

Take Quiz To Earn Credits!

Turn Your Knowledge into Earnings.

tuteehub_quiz

Tuteehub forum answer Answers

Post Answer

No matter what stage you're at in your education or career, TuteeHub will help you reach the next level that you're aiming for. Simply,Choose a subject/topic and get started in self-paced practice sessions to improve your knowledge and scores.