STEADY state capacitor will be open and INDUCTOR will SHORT circuited. V across 2C will be = 12V .

"> STEADY state capacitor will be open and INDUCTOR will SHORT circuited. V across 2C will be = 12V .

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In the circuit shown in the figure, steady-state was reached when the switch S was open. The switch was closed at t = 0. The initial value of the current through the capacitor 2 C is

Electronics & Communication Engineering Networks Analysis And Synthesis in Electronics & Communication Engineering . 9 months ago

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At STEADY state capacitor will be open and INDUCTOR will SHORT circuited. V across 2C will be = 12V .

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Posted on 08 Jul 2024, this text provides information on Electronics & Communication Engineering related to Networks Analysis And Synthesis in Electronics & Communication Engineering. Please note that while accuracy is prioritized, the data presented might not be entirely correct or up-to-date. This information is offered for general knowledge and informational purposes only, and should not be considered as a substitute for professional advice.

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