GIVEN by:\(V_0=\frac{-R_F}{R_i}\) -----(1)For Non inverting Op-Amp,The output is given by:\(V_0=1+\frac{R_F}{R_i}\) -----(2)Calculation:Given:RF = 105Ri = 103For inverting Op-Amp,The output can be calculated from EQUATION (1):\(V_0=\frac{-10^5}{10^3}\)V0 = - 100 ----(3)For non-inverting Op-Amp,The output can be calculated from equation (2):\(V_0=1+\frac{10^5}{10^3}\)Vo = 101 ---(4)From equations (3) and (4) we can SAY that.The MAGNITUDE of inverting and non-inverting gains are nearly the same.Hence the solution is OPTION (1).

"> GIVEN by:\(V_0=\frac{-R_F}{R_i}\) -----(1)For Non inverting Op-Amp,The output is given by:\(V_0=1+\frac{R_F}{R_i}\) -----(2)Calculation:Given:RF = 105Ri = 103For inverting Op-Amp,The output can be calculated from EQUATION (1):\(V_0=\frac{-10^5}{10^3}\)V0 = - 100 ----(3)For non-inverting Op-Amp,The output can be calculated from equation (2):\(V_0=1+\frac{10^5}{10^3}\)Vo = 101 ---(4)From equations (3) and (4) we can SAY that.The MAGNITUDE of inverting and non-inverting gains are nearly the same.Hence the solution is OPTION (1).

">

A high gain OpAmp has Rf = 105 Ω & Ri = 103 Ω. The correct statement is:

Electronics & Communication Engineering Op-Amp And Its Applications in Electronics & Communication Engineering . 7 months ago

  2   0   0   0   0 tuteeHUB earn credit +10 pts

5 Star Rating 1 Rating

Concept:Operational Amplifier (Op-Amp):An operational amplifier is an integrated circuit (IC) that operates as a voltage amplifier.An op-amp has a differential input. That is, it has two inputs of opposite polarity.An op-amp has a single output and a very high gain, which means that the output signal is much higher than input signal.For Inverting Op-Amp, The output is GIVEN by:\(V_0=\frac{-R_F}{R_i}\) -----(1)For Non inverting Op-Amp,The output is given by:\(V_0=1+\frac{R_F}{R_i}\) -----(2)Calculation:Given:RF = 105Ri = 103For inverting Op-Amp,The output can be calculated from EQUATION (1):\(V_0=\frac{-10^5}{10^3}\)V0 = - 100 ----(3)For non-inverting Op-Amp,The output can be calculated from equation (2):\(V_0=1+\frac{10^5}{10^3}\)Vo = 101 ---(4)From equations (3) and (4) we can SAY that.The MAGNITUDE of inverting and non-inverting gains are nearly the same.Hence the solution is OPTION (1).

Posted on 24 Oct 2024, this text provides information on Electronics & Communication Engineering related to Op-Amp And Its Applications in Electronics & Communication Engineering. Please note that while accuracy is prioritized, the data presented might not be entirely correct or up-to-date. This information is offered for general knowledge and informational purposes only, and should not be considered as a substitute for professional advice.

Take Quiz To Earn Credits!

Turn Your Knowledge into Earnings.

tuteehub_quiz

Tuteehub forum answer Answers

Post Answer

No matter what stage you're at in your education or career, TuteeHub will help you reach the next level that you're aiming for. Simply,Choose a subject/topic and get started in self-paced practice sessions to improve your knowledge and scores.