HR)0 - 22 - 4Rainfall (cm)6.25.0 \(\therefore \phi - index = \frac{{P - R}}{t}\)whereP = Rainfall depthR = Runoff deptht = Duration of rainfallR = P - ϕindex × tR = (6.2 + 5.0) - 1.2 × 4R = 11.2 - 4.8R = 6.4 cmRunoff volume = 6.4 × 10-2 × 250 × 106Runoff volume = 1600 × 104 m3Runoff volume = 1600 hectare - meter(1 hectare = 104 m2)

"> HR)0 - 22 - 4Rainfall (cm)6.25.0 \(\therefore \phi - index = \frac{{P - R}}{t}\)whereP = Rainfall depthR = Runoff deptht = Duration of rainfallR = P - ϕindex × tR = (6.2 + 5.0) - 1.2 × 4R = 11.2 - 4.8R = 6.4 cmRunoff volume = 6.4 × 10-2 × 250 × 106Runoff volume = 1600 × 104 m3Runoff volume = 1600 hectare - meter(1 hectare = 104 m2)

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A 4-hour rainfall in a catchment of 250 sq. km, produces rainfall depths of 6.2 cm and 5.0 cm in successive 2-hour unit period. Assuming the φ index of the soil to be 1.2 cm per hour, the runoff volume in hectare meter will be

Energy Engineering Hydrograph in Energy Engineering . 7 months ago

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Time (HR)0 - 22 - 4Rainfall (cm)6.25.0 \(\therefore \phi - index = \frac{{P - R}}{t}\)whereP = Rainfall depthR = Runoff deptht = Duration of rainfallR = P - ϕindex × tR = (6.2 + 5.0) - 1.2 × 4R = 11.2 - 4.8R = 6.4 cmRunoff volume = 6.4 × 10-2 × 250 × 106Runoff volume = 1600 × 104 m3Runoff volume = 1600 hectare - meter(1 hectare = 104 m2)

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Posted on 17 Nov 2024, this text provides information on Energy Engineering related to Hydrograph in Energy Engineering. Please note that while accuracy is prioritized, the data presented might not be entirely correct or up-to-date. This information is offered for general knowledge and informational purposes only, and should not be considered as a substitute for professional advice.

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