E = 2G (1 + μ). For E = G, μ = 0 which is not possible for elastic MATERIAL.E = 3K (1 – 2μ). For E ≈ K, μ = 0.30 to 0.34. Hence it is possible for elastic material. "> E = 2G (1 + μ). For E = G, μ = 0 which is not possible for elastic MATERIAL.E = 3K (1 – 2μ). For E ≈ K, μ = 0.30 to 0.34. Hence it is possible for elastic material. ">
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If E, G and K denote Young’s modulus of elasticity, Modulus of rigidity and Bulk modulus, respectively, for an elastic material then which one of the following can be possibly true?

Engineering Physics Elastic Limit in Engineering Physics 8 months ago

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E = 2G (1 + μ). For E = G, μ = 0 which is not possible for elastic MATERIAL.E = 3K (1 – 2μ). For E ≈ K, μ = 0.30 to 0.34. Hence it is possible for elastic material.
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Posted on 01 Nov 2024, this text provides information on Engineering Physics related to Elastic Limit in Engineering Physics. Please note that while accuracy is prioritized, the data presented might not be entirely correct or up-to-date. This information is offered for general knowledge and informational purposes only, and should not be considered as a substitute for professional advice.

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