IMMERSED in a liquid is equal to the weight of the liquid DISPLACED by the body.It is clear that the apparent loss of weight is DUE to the FORCE of buoyancy, which is a NET result of the pressure forces acting on the surface of the body.Buoyancy ForceFB= γbody × VFluid displacedCalculation‑Given:Wempty = 1.5 N, Wwater = 1.1 N, V = ?Now, we know thatFor air,Net Buoyancy force = Actual weight – Weight in airFB= Wact – 1.5∴ Wact = 1.5 N, (∵ γair is negligible)For waterFB= Wact – 1.1∴ γwater × Vcontainer = 0.4 N ∴ Vcontainer = \(\frac{0.4}{9810}\) m3 ∴ Vcontainer = 40.8 cm3 (∵ 1 cm3 = 10-6 m3)

"> IMMERSED in a liquid is equal to the weight of the liquid DISPLACED by the body.It is clear that the apparent loss of weight is DUE to the FORCE of buoyancy, which is a NET result of the pressure forces acting on the surface of the body.Buoyancy ForceFB= γbody × VFluid displacedCalculation‑Given:Wempty = 1.5 N, Wwater = 1.1 N, V = ?Now, we know thatFor air,Net Buoyancy force = Actual weight – Weight in airFB= Wact – 1.5∴ Wact = 1.5 N, (∵ γair is negligible)For waterFB= Wact – 1.1∴ γwater × Vcontainer = 0.4 N ∴ Vcontainer = \(\frac{0.4}{9810}\) m3 ∴ Vcontainer = 40.8 cm3 (∵ 1 cm3 = 10-6 m3)

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A piece of ore weighing 1.5 N in air and 1.1 N in water. Its volume is:

Fluid Mechanics Buoyancy And Floatation in Fluid Mechanics . 7 months ago

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Concept:Loss of weight by Archimedes principle:Archimedes principle states that the apparent loss of weight of a body when IMMERSED in a liquid is equal to the weight of the liquid DISPLACED by the body.It is clear that the apparent loss of weight is DUE to the FORCE of buoyancy, which is a NET result of the pressure forces acting on the surface of the body.Buoyancy ForceFB= γbody × VFluid displacedCalculation‑Given:Wempty = 1.5 N, Wwater = 1.1 N, V = ?Now, we know thatFor air,Net Buoyancy force = Actual weight – Weight in airFB= Wact – 1.5∴ Wact = 1.5 N, (∵ γair is negligible)For waterFB= Wact – 1.1∴ γwater × Vcontainer = 0.4 N ∴ Vcontainer = \(\frac{0.4}{9810}\) m3 ∴ Vcontainer = 40.8 cm3 (∵ 1 cm3 = 10-6 m3)

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