KJ (from the gas)CHANGE in Internal energy (u2 – u1) = -20 kJ (drop)According to first law of thermodynamicsδQ = dU + δW-40 = -20 + δW⇒ δW = -20 kJ ---(I) SINCE, the process is isobaric (as pressure REMAINS same)So, isobaric work done δW = PdV = P (Vfinal - Vinitial) δW = P (Vfinal - Vinitial) = -20 kJ1000 kPa × (0.2 – y) M3 = -20 kJ\(0.2 - y = \frac{{ - 20}}{{1000}} = - 0.02 \Rightarrow y = 0.22\)∴Initial volume (y) = 0.22 m3

"> KJ (from the gas)CHANGE in Internal energy (u2 – u1) = -20 kJ (drop)According to first law of thermodynamicsδQ = dU + δW-40 = -20 + δW⇒ δW = -20 kJ ---(I) SINCE, the process is isobaric (as pressure REMAINS same)So, isobaric work done δW = PdV = P (Vfinal - Vinitial) δW = P (Vfinal - Vinitial) = -20 kJ1000 kPa × (0.2 – y) M3 = -20 kJ\(0.2 - y = \frac{{ - 20}}{{1000}} = - 0.02 \Rightarrow y = 0.22\)∴Initial volume (y) = 0.22 m3

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A gas is compressed in a frictionless piston from an initial state of y m3 and 1 MPa to a final state of 0.2 m3 and 1 MPa. There is a transfer of 40 kJ of heat from the gas and a drop of 20kJ in internal energy. What is the initial state volume of the gas?

Fluid Mechanics First Law Thermodynamics in Fluid Mechanics 8 months ago

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Concept:According to the first law of thermodynamicsδQ = dU + δWIsobaric work doneδW = PdV = P (Vfinal - Vinitial) Calculation:Initial condition ⇒ P1 = 1 MPa, V1 = y m3Final condition ⇒ P2 = 1 MPa, V2 = 0.2 m3Heat Transfer = -40 KJ (from the gas)CHANGE in Internal energy (u2 – u1) = -20 kJ (drop)According to first law of thermodynamicsδQ = dU + δW-40 = -20 + δW⇒ δW = -20 kJ ---(I) SINCE, the process is isobaric (as pressure REMAINS same)So, isobaric work done δW = PdV = P (Vfinal - Vinitial) δW = P (Vfinal - Vinitial) = -20 kJ1000 kPa × (0.2 – y) M3 = -20 kJ\(0.2 - y = \frac{{ - 20}}{{1000}} = - 0.02 \Rightarrow y = 0.22\)∴Initial volume (y) = 0.22 m3

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Posted on 23 Nov 2024, this text provides information on Fluid Mechanics related to First Law Thermodynamics in Fluid Mechanics. Please note that while accuracy is prioritized, the data presented might not be entirely correct or up-to-date. This information is offered for general knowledge and informational purposes only, and should not be considered as a substitute for professional advice.

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