SYSTEM gives the relationship between heat (Q), Internal energy (U) & work done (W) it is related by the equationdQ = ΔU + dWCalculation:⇒ Here Q = +2500 J (∵ Heat is supplied to the system)ΔU = + 1500 (∵ energy increases)Now 2500 J = 1500 J + W⇒ W = 1000 JThis work done by gas will be UTILIZED to raise the piston.Work done by gas = work done by piston mass⇒ 100 J = mgx\(\Rightarrow x = \frac{{1000}}{{100 \times 9.81}} = 1M\)

"> SYSTEM gives the relationship between heat (Q), Internal energy (U) & work done (W) it is related by the equationdQ = ΔU + dWCalculation:⇒ Here Q = +2500 J (∵ Heat is supplied to the system)ΔU = + 1500 (∵ energy increases)Now 2500 J = 1500 J + W⇒ W = 1000 JThis work done by gas will be UTILIZED to raise the piston.Work done by gas = work done by piston mass⇒ 100 J = mgx\(\Rightarrow x = \frac{{1000}}{{100 \times 9.81}} = 1M\)

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A gas is contained in a cylinder with a moveable piston of 100 kg mass. When 2500 J of heat flows into the gas, the internal energy of the gas increases by 1500 J. What is the distance through which the piston rises?

Fluid Mechanics First Law Thermodynamics in Fluid Mechanics 8 months ago

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Concept:The first law for a closed SYSTEM gives the relationship between heat (Q), Internal energy (U) & work done (W) it is related by the equationdQ = ΔU + dWCalculation:⇒ Here Q = +2500 J (∵ Heat is supplied to the system)ΔU = + 1500 (∵ energy increases)Now 2500 J = 1500 J + W⇒ W = 1000 JThis work done by gas will be UTILIZED to raise the piston.Work done by gas = work done by piston mass⇒ 100 J = mgx\(\Rightarrow x = \frac{{1000}}{{100 \times 9.81}} = 1M\)

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Posted on 19 Nov 2024, this text provides information on Fluid Mechanics related to First Law Thermodynamics in Fluid Mechanics. Please note that while accuracy is prioritized, the data presented might not be entirely correct or up-to-date. This information is offered for general knowledge and informational purposes only, and should not be considered as a substitute for professional advice.

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