CONCEPT:To keep the temperature of the room as CONSTANT, the heat loss MUST be equal to the total heat dissipated in the room.Amount of total heat generated in the room = Qrefri + Qheater + QTV + QfanCalculation:GIVEN:Qrefri = 250 W, Qheater = 1 kW = 1000 W, QTV = 120 W, Qfan = 50 WTotal power dissipated from the appliances = 250 + 1000 + 120 + 50 = 1420 W = 1420 J/s\( \Rightarrow {\rm{Heat\;loss}} = 1420~{\rm{J}}/{\rm{s}} = \frac{{1420 \times 3600}}{{1000}} = 5112~kJ/hr\)