14000 kJ.As per First Law of Thermodynamics:δQ = dU + δW-5000 = dU + (-14000)dU = 9000 kJ.Due to this CHANGE in INTERNAL energy, the system temperature will be RAISED but this is due to the work done on the system (by paddle wheel).Here the boundary is rigid, the work done by the system is not changing its CONTROL volume, therefore the work done by the system (pdV work) is zero.

"> 14000 kJ.As per First Law of Thermodynamics:δQ = dU + δW-5000 = dU + (-14000)dU = 9000 kJ.Due to this CHANGE in INTERNAL energy, the system temperature will be RAISED but this is due to the work done on the system (by paddle wheel).Here the boundary is rigid, the work done by the system is not changing its CONTROL volume, therefore the work done by the system (pdV work) is zero.

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A tank containing air is stirred by a paddle wheel. The work input to the wheel is 14000 kJ and heat transferred to the surrounding from the tank is 5000 kJ. The change in internal energy of the system (air) is:

Fluid Mechanics First Law Thermodynamics in Fluid Mechanics 7 months ago

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Cobcept:In this case, the volume is constant.δQ = -5000 kJ, and Work done into the system = -14000 kJ.As per First Law of Thermodynamics:δQ = dU + δW-5000 = dU + (-14000)dU = 9000 kJ.Due to this CHANGE in INTERNAL energy, the system temperature will be RAISED but this is due to the work done on the system (by paddle wheel).Here the boundary is rigid, the work done by the system is not changing its CONTROL volume, therefore the work done by the system (pdV work) is zero.

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Posted on 01 Dec 2024, this text provides information on Fluid Mechanics related to First Law Thermodynamics in Fluid Mechanics. Please note that while accuracy is prioritized, the data presented might not be entirely correct or up-to-date. This information is offered for general knowledge and informational purposes only, and should not be considered as a substitute for professional advice.

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