PLUG, there is an appreciable drop in pressure and the flow is SAID to be throttled.Throttling is done in an insulated pipe with a partially open valve.From S.F.E.E,\(\LEFT( {{h_1} + \;\frac{{v_1^2}}{2} + G{z_1}} \right) + \frac{{\delta Q}}{{dm}} = \left( {{h_2} + \frac{{v_2^2}}{2} + g{z_2}} \right) + \frac{{\delta W}}{{dm}}\)\(\frac{{\delta Q}}{{dm}} = 0,\frac{{\delta W}}{{dm}} = 0\)As the potential and kinetic energy changes are negligible,Thus S.F.E.E. becomes, h1 = h2i.e. ENTHALPY remains constant.