B or C. Since the area under each curve represents the work for each process, the amount of work involved in each case is not a function of the end states of the process and it depends on the path which the system follows in going from state 1 to state 2. For this reason, work is called a path function, and δW is an inexact or imperfect differential.According to the question:For the given problem STATEMENT i.e. “work done in an adiabatic process”, the path is fixed i.e. adiabatic process.And for a given path work done will be dependent on the end states only.So, the work done in an adiabatic process between two given end states depends on end states only.or, from FIRST law of thermodynamics,δQ = ΔU + δW, for an adiabatic process δQ = 0.i.e. 0 = ΔU + δW⇒ δW = - ΔU = U1 - U2Since, work done is equal to change in internal energy and internal energy is a point function or state function.So, the work done in an adiabatic process between two given end states depends on end states only.

"> B or C. Since the area under each curve represents the work for each process, the amount of work involved in each case is not a function of the end states of the process and it depends on the path which the system follows in going from state 1 to state 2. For this reason, work is called a path function, and δW is an inexact or imperfect differential.According to the question:For the given problem STATEMENT i.e. “work done in an adiabatic process”, the path is fixed i.e. adiabatic process.And for a given path work done will be dependent on the end states only.So, the work done in an adiabatic process between two given end states depends on end states only.or, from FIRST law of thermodynamics,δQ = ΔU + δW, for an adiabatic process δQ = 0.i.e. 0 = ΔU + δW⇒ δW = - ΔU = U1 - U2Since, work done is equal to change in internal energy and internal energy is a point function or state function.So, the work done in an adiabatic process between two given end states depends on end states only.

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In an adiabatic process, the work done for a given pair of end states depends on:

Fluid Mechanics First Law Thermodynamics in Fluid Mechanics . 7 months ago

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Explanation:Work transfer and heat transfer are a path function.Example:It is possible to take a system from state 1 to state 2 along many quasi-static paths such as A, B or C. Since the area under each curve represents the work for each process, the amount of work involved in each case is not a function of the end states of the process and it depends on the path which the system follows in going from state 1 to state 2. For this reason, work is called a path function, and δW is an inexact or imperfect differential.According to the question:For the given problem STATEMENT i.e. “work done in an adiabatic process”, the path is fixed i.e. adiabatic process.And for a given path work done will be dependent on the end states only.So, the work done in an adiabatic process between two given end states depends on end states only.or, from FIRST law of thermodynamics,δQ = ΔU + δW, for an adiabatic process δQ = 0.i.e. 0 = ΔU + δW⇒ δW = - ΔU = U1 - U2Since, work done is equal to change in internal energy and internal energy is a point function or state function.So, the work done in an adiabatic process between two given end states depends on end states only.

Posted on 01 Dec 2024, this text provides information on Fluid Mechanics related to First Law Thermodynamics in Fluid Mechanics. Please note that while accuracy is prioritized, the data presented might not be entirely correct or up-to-date. This information is offered for general knowledge and informational purposes only, and should not be considered as a substitute for professional advice.

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