ENERGY is given by:\(E = y + \frac{{{V^2}}}{{2g}} = y + \frac{{{Q^2}}}{{2g{A^2}}}\)where,y = Depth of flowQ = Discharge of flowA = Area of cross-sectionV = Velocity of flowand, Area of cross section of trapezoidal section is given by:A = By + my2where, B = Bottom WIDTH of channelm = Side slope of channel Calculation:Given Data:y = 1.5 mBottom width, B = 6 mQ = 15 m3/secSide slope, m = 1Let's FIND area of the cross section from the above formula A = (6 × 1.5) + (1 × 1.52) = 11.25 m2Now, Putting all these data in Specific Energy formula, we get,\(E = 1.5 + \frac{{{{15}^2}}}{{2 \TIMES 9.81 \times {{11.25}^2}}} = 1.591\;m = 1.6\;m\)