TRANSFER the input mechanical energy of a motor or of an engine (Kinetic energy) into PRESSURE energy. Centrifugal pump is type of dynamic pressure pump. The efficiency of pump is given as, η = \(\frac{Water~Power}{Shaft~Power}\)where, Water power = ρgQH and Shaft Power = rating of pumpCalculation:Given: \(Q = 0.0125\frac{{{m^3}}}{s}\), Shaft Power = 5 kW = 5000 W, H = 30 m, ρ = 1000 kg/m3∴ \(η = \frac{{ρ \times g \times Q \times H}}{{{P_S}}}\)\(η = \frac{{1000 \times 9.81 \times 0.0125 \times 30}}{{5000}}\)\(η = 0.73575 \approx 0.74\)\(η = 74\%\)TurbinePumpHydraulic efficiency., \({\eta _{hy}} = \frac{{Runner~Power}}{{Water~Power}} = \frac{{\rho Q({V_{w1}}{u_1} + {V_{W2}}{u_2})}}{{\rho QgH}}\)MANOMETRIC efficiency., \({\eta _{mano}} = \frac{{Water~Power}}{{Impeller~power}} = \frac{{\rho Qg{H_m}}}{{\rho Q({V_{w2}} \times {u_2})}}\)Mechanical efficiency., \({\eta _{mech}} = \frac{{Shaft~Power}}{{Runner~Power}} = \frac{{ShaftPower}}{{\rho Q({V_{w1}}{u_1} + {V_{w2}}{u_2})}}\)Mechanical efficiency., \({\eta _{mech}} = \frac{{Impeller~Power}}{{Shaft~Power}} = \frac{{{V_{w2}} \times {u_2}}}{{ShaftPower}}\)Overall efficiency., \({\eta _o} = {\eta _{mano}} \times {\eta _{mech}}\) Overall efficiency., \({\eta _o} = {\eta _{mano}} \times {\eta _{mech}}\)

"> TRANSFER the input mechanical energy of a motor or of an engine (Kinetic energy) into PRESSURE energy. Centrifugal pump is type of dynamic pressure pump. The efficiency of pump is given as, η = \(\frac{Water~Power}{Shaft~Power}\)where, Water power = ρgQH and Shaft Power = rating of pumpCalculation:Given: \(Q = 0.0125\frac{{{m^3}}}{s}\), Shaft Power = 5 kW = 5000 W, H = 30 m, ρ = 1000 kg/m3∴ \(η = \frac{{ρ \times g \times Q \times H}}{{{P_S}}}\)\(η = \frac{{1000 \times 9.81 \times 0.0125 \times 30}}{{5000}}\)\(η = 0.73575 \approx 0.74\)\(η = 74\%\)TurbinePumpHydraulic efficiency., \({\eta _{hy}} = \frac{{Runner~Power}}{{Water~Power}} = \frac{{\rho Q({V_{w1}}{u_1} + {V_{W2}}{u_2})}}{{\rho QgH}}\)MANOMETRIC efficiency., \({\eta _{mano}} = \frac{{Water~Power}}{{Impeller~power}} = \frac{{\rho Qg{H_m}}}{{\rho Q({V_{w2}} \times {u_2})}}\)Mechanical efficiency., \({\eta _{mech}} = \frac{{Shaft~Power}}{{Runner~Power}} = \frac{{ShaftPower}}{{\rho Q({V_{w1}}{u_1} + {V_{w2}}{u_2})}}\)Mechanical efficiency., \({\eta _{mech}} = \frac{{Impeller~Power}}{{Shaft~Power}} = \frac{{{V_{w2}} \times {u_2}}}{{ShaftPower}}\)Overall efficiency., \({\eta _o} = {\eta _{mano}} \times {\eta _{mech}}\) Overall efficiency., \({\eta _o} = {\eta _{mano}} \times {\eta _{mech}}\)

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A centrifugal pump is required to lift 0.0125 m3/s of water from a well with depth 30 m. If rating of the pump motor is 5 kW, and the density of water is 1000 kg/m3, the efficiency of the pump will be nearly

Fluid Mechanics Turbomachinery in Fluid Mechanics . 7 months ago

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Concept:Pump is defined as a device which TRANSFER the input mechanical energy of a motor or of an engine (Kinetic energy) into PRESSURE energy. Centrifugal pump is type of dynamic pressure pump. The efficiency of pump is given as, η = \(\frac{Water~Power}{Shaft~Power}\)where, Water power = ρgQH and Shaft Power = rating of pumpCalculation:Given: \(Q = 0.0125\frac{{{m^3}}}{s}\), Shaft Power = 5 kW = 5000 W, H = 30 m, ρ = 1000 kg/m3∴ \(η = \frac{{ρ \times g \times Q \times H}}{{{P_S}}}\)\(η = \frac{{1000 \times 9.81 \times 0.0125 \times 30}}{{5000}}\)\(η = 0.73575 \approx 0.74\)\(η = 74\%\)TurbinePumpHydraulic efficiency., \({\eta _{hy}} = \frac{{Runner~Power}}{{Water~Power}} = \frac{{\rho Q({V_{w1}}{u_1} + {V_{W2}}{u_2})}}{{\rho QgH}}\)MANOMETRIC efficiency., \({\eta _{mano}} = \frac{{Water~Power}}{{Impeller~power}} = \frac{{\rho Qg{H_m}}}{{\rho Q({V_{w2}} \times {u_2})}}\)Mechanical efficiency., \({\eta _{mech}} = \frac{{Shaft~Power}}{{Runner~Power}} = \frac{{ShaftPower}}{{\rho Q({V_{w1}}{u_1} + {V_{w2}}{u_2})}}\)Mechanical efficiency., \({\eta _{mech}} = \frac{{Impeller~Power}}{{Shaft~Power}} = \frac{{{V_{w2}} \times {u_2}}}{{ShaftPower}}\)Overall efficiency., \({\eta _o} = {\eta _{mano}} \times {\eta _{mech}}\) Overall efficiency., \({\eta _o} = {\eta _{mano}} \times {\eta _{mech}}\)

Posted on 22 Oct 2024, this text provides information on Fluid Mechanics related to Turbomachinery in Fluid Mechanics. Please note that while accuracy is prioritized, the data presented might not be entirely correct or up-to-date. This information is offered for general knowledge and informational purposes only, and should not be considered as a substitute for professional advice.

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