SUBSTITUTING the value of x = 8 and y = 2 in the given equation we have 8 + (4 × 2) - 2k = 0⇒ 8 + 8 - 2k = 0⇒ 2k = 16⇒ k = (16/2) = 8Value of k2 = 82 = 64∴ Required value = 64 "> SUBSTITUTING the value of x = 8 and y = 2 in the given equation we have 8 + (4 × 2) - 2k = 0⇒ 8 + 8 - 2k = 0⇒ 2k = 16⇒ k = (16/2) = 8Value of k2 = 82 = 64∴ Required value = 64 ">
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If (8, 2) is a solution of x + 4y - 2k = 0, then find the value of k2.

General Aptitude Algebra in General Aptitude . 2 months ago

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SUBSTITUTING the value of x = 8 and y = 2 in the given equation we have 8 + (4 × 2) - 2k = 0⇒ 8 + 8 - 2k = 0⇒ 2k = 16⇒ k = (16/2) = 8Value of k2 = 82 = 64∴ Required value = 64
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