C = 8Formula:A3 + B3 + c3 – 3ABC = (a + b + c) (a2 + b2 + C2 – ab – bc – ca)Calculation:(a3 + b3 + c3 – 3abc)/(ab + bc + ca – a2 – b2 – c2)⇒ (a + b + c) (a2 + b2 + c2 – ab – bc – ca)/[- (a2 + b2 + c2 – ab – bc – ca)]⇒ -(5 + 4 + 8)⇒ -17∴ The value of (a3 + b3 + c3 – 3abc)/(ab + bc + ca – a2 – b2 – c2) is -17.

"> C = 8Formula:A3 + B3 + c3 – 3ABC = (a + b + c) (a2 + b2 + C2 – ab – bc – ca)Calculation:(a3 + b3 + c3 – 3abc)/(ab + bc + ca – a2 – b2 – c2)⇒ (a + b + c) (a2 + b2 + c2 – ab – bc – ca)/[- (a2 + b2 + c2 – ab – bc – ca)]⇒ -(5 + 4 + 8)⇒ -17∴ The value of (a3 + b3 + c3 – 3abc)/(ab + bc + ca – a2 – b2 – c2) is -17.

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If a = 5, b = 4, c = 8 then find the value of (a3 + b3 + c3 – 3abc)/(ab + bc + ca – a2 – b2 – c2).A. 15B. 17C. -17D. -15

General Aptitude Algebra in General Aptitude . 2 months ago

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Given:a = 5, b = 4, C = 8Formula:A3 + B3 + c3 – 3ABC = (a + b + c) (a2 + b2 + C2 – ab – bc – ca)Calculation:(a3 + b3 + c3 – 3abc)/(ab + bc + ca – a2 – b2 – c2)⇒ (a + b + c) (a2 + b2 + c2 – ab – bc – ca)/[- (a2 + b2 + c2 – ab – bc – ca)]⇒ -(5 + 4 + 8)⇒ -17∴ The value of (a3 + b3 + c3 – 3abc)/(ab + bc + ca – a2 – b2 – c2) is -17.

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Posted on 30 Oct 2024, this text provides information on General Aptitude related to Algebra in General Aptitude. Please note that while accuracy is prioritized, the data presented might not be entirely correct or up-to-date. This information is offered for general knowledge and informational purposes only, and should not be considered as a substitute for professional advice.

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