42 + 4p + 12 = 0⇒ p = -7AND equation x2 + px + q = 0 has equal roots⇒ Discriminant = b2 – 4ac (Discriminant = 0 when roots of a QUADRATIC equation are equal)⇒ D = (-7)2 – 4 × 1 × q = 0⇒ q = 49/4∴ q = 49/4

"> 42 + 4p + 12 = 0⇒ p = -7AND equation x2 + px + q = 0 has equal roots⇒ Discriminant = b2 – 4ac (Discriminant = 0 when roots of a QUADRATIC equation are equal)⇒ D = (-7)2 – 4 × 1 × q = 0⇒ q = 49/4∴ q = 49/4

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If one of the roots of the equation x2 + px + 12 = 0 is 4, while the equation x2 + px + q = 0 has equal roots, then find the value of q.

General Aptitude Algebra in General Aptitude 10 months ago

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Since 4 is a root of x2 + px + 12 = 0⇒ 42 + 4p + 12 = 0⇒ p = -7AND equation x2 + px + q = 0 has equal roots⇒ Discriminant = b2 – 4ac (Discriminant = 0 when roots of a QUADRATIC equation are equal)⇒ D = (-7)2 – 4 × 1 × q = 0⇒ q = 49/4∴ q = 49/4

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